Elmer Discussion Forum

If you are putting an object in the cube, then I think it would work. Yes that's exactly what I want do do. You may want to read through this thread, it has some similarities. http://www.elmerfem.org/forum/viewtopic.php?t=8014&start=10 Ok awesome I will have a look on Monday and get back to you...

Ok so I tried with a sphere but cannot get any convergence. Here's the boundary condition: Boundary Condition 1 Target Boundaries(1) = $ surf Name = surface Magnetic Field Strength 1 = Real 1.0 Magnetic Field Strength 2 = Real 1.0 Magnetic Field Strength 3 = Real 1.0 End And this is the geometry I u...

Ah ok.

I'll give that a shot.

Thanks so much for your help!!

Cheers,
Nick

Hmm I'll give that a try again.Towards the end of last year, I made a post about specifying the components of the H-field through the boundary conditions so that the field could be created in an arbitrary direction, but Peter (raback) had this to say: Hi The coordinate system is standard cartesian o...

Hi Kevin,

Thanks so much for your help!

I did try your modification to Boundary Condition 5 but have not had any luck. I'll give your other suggestion a try too.

I'm trying to create an H-field at an arbitrary angle which is why I wanted to use the cube. I'll give a sphere a try.

Cheers,
Nick

Hi all, I have simple cube where a rotational transformation has been applied to the X,Y, and Z axes. The rotation about each axis is Pi/4 radians. I then have boundary conditions on the surfaces of the cube to create an H-field. If I don't apply the rotational transformation to the cube, Elmer solv...

Hi all,

I'm still struggling to get this to work

Does anyone have any suggestions or examples?

Hi Peter,

Alright, thanks very much.

Edit: I've sat fiddling with the BCs but am still not able to create a uniform H-field at an arbitrary angle in 3D. Would you perhaps have some insight for me as to how I can do it other than brute forcing all the combinations

Cheers,
Nick

Ok so I have a follow-up question. If I'm understanding the manual correctly (page 122 just below EQ 18.56), it is saying that magnetic field strength xyz is specifying the tangential components? Also, what coordinate system is this made with respect to? Does xyz correspond to the global xyz system ...

Oh wow that's some basic calculus I forgot! Thanks Kevin