Contact Mechanics  Friction Test

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 Joined: 25 Jan 2019, 01:28
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Re: Contact Mechanics  Friction Test
Did the same steps, received the same results, normal loads way too high. Built a similar model from scratch and made my own sif, same result, normal loads way too high.
Re: Contact Mechanics  Friction Test
Thank you so much for your effort.
Unfortunately I cannot find out how and where "NormalLoadVar % Values" gets its values. I also tried to put the Normalload as a Boundary Condition at the bottom of the cube (Force 3 = 9.81 * 7810.0 and Force 3 = 9.81 * 7810.0 * 10.0e6, because I did not know if volume is considered in a bc) instead of the body force. But the values are stil way too high. I don't know where NormalLoadVar" gets its values from..
Unfortunately I cannot find out how and where "NormalLoadVar % Values" gets its values. I also tried to put the Normalload as a Boundary Condition at the bottom of the cube (Force 3 = 9.81 * 7810.0 and Force 3 = 9.81 * 7810.0 * 10.0e6, because I did not know if volume is considered in a bc) instead of the body force. But the values are stil way too high. I don't know where NormalLoadVar" gets its values from..
Re: Contact Mechanics  Friction Test
I think this is the first time NormalLoadVar is called in SolverUtils:
NormalLoadVar => VariableGet( Model % Variables,&
TRIM(VarName)//' Contact Normalload')
But "Displacement Contact Normalload" is a variable that is calculated and outputted in vtu or if you want through SaveScalars, but not a variable you could set as a bc. If you try to set it as a bc, you get an error. I cannot find another line where NormalLoadVar gets any values..
NormalLoadVar => VariableGet( Model % Variables,&
TRIM(VarName)//' Contact Normalload')
But "Displacement Contact Normalload" is a variable that is calculated and outputted in vtu or if you want through SaveScalars, but not a variable you could set as a bc. If you try to set it as a bc, you get an error. I cannot find another line where NormalLoadVar gets any values..

 Posts: 651
 Joined: 25 Jan 2019, 01:28
 Antispam: Yes
Re: Contact Mechanics  Friction Test
Do loop starting at line 3052 in Subroutine CalculateContactPressure
sums the nodal forces into NodalForce then calculate NormalLoadVector
DO i=1,n
j = NormalLoadVar % Perm( Indexes(i) )
IF( .NOT. NodeDone( Indexes(i) ) ) THEN
NodeDone( Indexes(i) ) = .TRUE.
WeightVar % Values(j) = 0.0_dp
NormalLoadVar % Values(j) = 0.0_dp
SlipLoadVar % Values(j) = 0.0_dp
END IF
k = FieldPerm( Indexes(i) )
IF( k == 0 .OR. j == 0 ) CYCLE
DO l=1,dofs
NodalForce(l) = LoadValues(dofs*(k1)+l)
END DO
IF( ThisRotatedContact ) THEN
NormalForce = NodalForce(1)
ELSE
NormalForce = SUM( NodalForce * Normal )
END IF
SlipForce = SQRT( SUM( NodalForce**2 )  NormalForce**2 )
NormalLoadVar % Values(j) = NormalLoadVar % Values(j)  &
s * Basis(i) * NormalForce
SlipLoadVar % Values(j) = SlipLoadVar % Values(j) + &
s * Basis(i) * SlipForce
WeightVar % Values(j) = WeightVar % Values(j) + s * Basis(i)
END DO
sums the nodal forces into NodalForce then calculate NormalLoadVector
DO i=1,n
j = NormalLoadVar % Perm( Indexes(i) )
IF( .NOT. NodeDone( Indexes(i) ) ) THEN
NodeDone( Indexes(i) ) = .TRUE.
WeightVar % Values(j) = 0.0_dp
NormalLoadVar % Values(j) = 0.0_dp
SlipLoadVar % Values(j) = 0.0_dp
END IF
k = FieldPerm( Indexes(i) )
IF( k == 0 .OR. j == 0 ) CYCLE
DO l=1,dofs
NodalForce(l) = LoadValues(dofs*(k1)+l)
END DO
IF( ThisRotatedContact ) THEN
NormalForce = NodalForce(1)
ELSE
NormalForce = SUM( NodalForce * Normal )
END IF
SlipForce = SQRT( SUM( NodalForce**2 )  NormalForce**2 )
NormalLoadVar % Values(j) = NormalLoadVar % Values(j)  &
s * Basis(i) * NormalForce
SlipLoadVar % Values(j) = SlipLoadVar % Values(j) + &
s * Basis(i) * SlipForce
WeightVar % Values(j) = WeightVar % Values(j) + s * Basis(i)
END DO
Re: Contact Mechanics  Friction Test
That is interesting. In the comment above it says
! The nodal loads may be given either in cartesian or nt coordinate system.
and in the comment above the Subroutine CalculateContactLoad() ist also says
! If we have normaltangential coordinate system then also the load is in
! the same coordinate system.
Maybe one needs to define the load differently, I mean instead of using Force 1,2,3 Force N or T or something like that? Is that even possible?
! The nodal loads may be given either in cartesian or nt coordinate system.
and in the comment above the Subroutine CalculateContactLoad() ist also says
! If we have normaltangential coordinate system then also the load is in
! the same coordinate system.
Maybe one needs to define the load differently, I mean instead of using Force 1,2,3 Force N or T or something like that? Is that even possible?
Re: Contact Mechanics  Friction Test
Well I tried to put Normal Force as a bc but still wrong results..
So after trying to get this Fortran Code for a second I am even more confused:
So CalculateContactPressure gets its normalloads from LoadValues, LoadValues is
LoadVar => CalculateContactLoad()
LoadValues => LoadVar % Values,
CalculateContactLoad calls CalculateLoads using LoadVar as the Parameter "NodalLoads"
LoadVar => VariableGet( Model % Variables, &
TRIM(VarName) // ' Contact Load',ThisOnly = .TRUE. ).
But you cannot set Displacement Contact Load anywhere, but only get it as an output. I don't quite understand the sense of calculating loads using loads that are to be calculated.
In line 6345 and following in subroutine SetNodalLoads it appears that they are calculating loads based on the body force one has defined. But I don't know when and where they are used, apparently not for the normalload we are outputting.
So after trying to get this Fortran Code for a second I am even more confused:
So CalculateContactPressure gets its normalloads from LoadValues, LoadValues is
LoadVar => CalculateContactLoad()
LoadValues => LoadVar % Values,
CalculateContactLoad calls CalculateLoads using LoadVar as the Parameter "NodalLoads"
LoadVar => VariableGet( Model % Variables, &
TRIM(VarName) // ' Contact Load',ThisOnly = .TRUE. ).
But you cannot set Displacement Contact Load anywhere, but only get it as an output. I don't quite understand the sense of calculating loads using loads that are to be calculated.
In line 6345 and following in subroutine SetNodalLoads it appears that they are calculating loads based on the body force one has defined. But I don't know when and where they are used, apparently not for the normalload we are outputting.
Re: Contact Mechanics  Friction Test
or as in line 5521 in ElasticSolve.F90. I wonder if one could just get the NodalLoad in SolverUtils like that too.

 Posts: 651
 Joined: 25 Jan 2019, 01:28
 Antispam: Yes
Re: Contact Mechanics  Friction Test
Changed Contact Friction = Logical True to Contact Friction = Logical False and the normal load and slip load are much more reasonable. The value of the coefficient of friction still does not change the results.

 Posts: 651
 Joined: 25 Jan 2019, 01:28
 Antispam: Yes
Re: Contact Mechanics  Friction Test
Using Contact Friction = Logical False, turned off the gravity (body force load) applied a Normal Force = Real 10. to the top face of the cube and the contact normal load is exactly 10.
Re: Contact Mechanics  Friction Test
If you turn off friction contact, the friction coefficients do not have any effect, because in the subroutine TangentContactSet the ifcondition
IF( FrictionContact .AND. &
ListGetLogical( BC,'Stick Contact Global',Found ) ) THEN
is not met (when there is no friction the tangent contact set is empty).
I tried the same thing but I don't get Displacement Contact Normalload = 10 neither in Paraview nor in my SaveScalarsOutput.. can you send me your sif?
IF( FrictionContact .AND. &
ListGetLogical( BC,'Stick Contact Global',Found ) ) THEN
is not met (when there is no friction the tangent contact set is empty).
I tried the same thing but I don't get Displacement Contact Normalload = 10 neither in Paraview nor in my SaveScalarsOutput.. can you send me your sif?