Elmer Install on Windows 10 not working

 Posts: 238
 Joined: 25 Jan 2019, 01:28
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Re: Elmer Install on Windows 10 not working
Another way is to partition the volume into two volumes so that there is a boundary where you want to apply the load.

 Posts: 238
 Joined: 25 Jan 2019, 01:28
 Antispam: Yes
Re: Elmer Install on Windows 10 not working
sif built in GUI using the free text input box Results

 Posts: 27
 Joined: 24 Jul 2019, 08:14
 Antispam: Yes
Re: Elmer Install on Windows 10 not working
I got your concept. Actually if the assembly is complex and have to define load point by coordinates (x,y,z) axis,,,,then it will be much simpler.
Whether MATC can define point nodal coordinates.
Whether MATC can define point nodal coordinates.

 Posts: 27
 Joined: 24 Jul 2019, 08:14
 Antispam: Yes
Re: Elmer Install on Windows 10 not working
Dear Friend,
I am new to drawing packages, I want your guidance, how you Partision Image by which Software package.
Kindly guide.
I am new to drawing packages, I want your guidance, how you Partision Image by which Software package.
Kindly guide.

 Posts: 238
 Joined: 25 Jan 2019, 01:28
 Antispam: Yes
Re: Elmer Install on Windows 10 not working
I use Salome, very powerful modeler and mesher.
It exports mesh to unv file and ElmerGrid will translate
https://salomeplatform.org/
It exports mesh to unv file and ElmerGrid will translate
https://salomeplatform.org/

 Posts: 27
 Joined: 24 Jul 2019, 08:14
 Antispam: Yes
Re: Elmer Install on Windows 10 not working
Dear Friend,
I have checked Target Coordinate Command by Physical Calculation.
The Load shows Equally Distributed and not Point load or line load at target Coordinate.
I have check for both linear and non linear, displacement is same.
Kindly check below and correct myself.
Header
CHECK KEYWORDS Warn
Mesh DB "." "."
Include Path ""
Results Directory ""
End
Simulation
Max Output Level = 5
Coordinate System = Cartesian
Coordinate Mapping(3) = 1 2 3
Simulation Type = Steady state
Steady State Max Iterations = 1
Output Intervals = 1
Timestepping Method = BDF
BDF Order = 1
Coordinate Scaling = 0.001 0.001 0.001
Solver Input File = case.sif
Post File = case.vtu
End
Constants
Gravity(4) = 0 1 0 9.82
Stefan Boltzmann = 5.67e08
Permittivity of Vacuum = 8.8542e12
Boltzmann Constant = 1.3807e23
Unit Charge = 1.602e19
End
Body 1
Target Bodies(1) = 1
Name = "Body 1"
Equation = 1
Material = 1
End
Solver 1
Equation = Linear elasticity
Procedure = "StressSolve" "StressSolver"
Variable = dofs 3 Displacement
Exec Solver = Always
Stabilize = True
Bubbles = False
Lumped Mass Matrix = False
Optimize Bandwidth = True
Steady State Convergence Tolerance = 1.0e5
Nonlinear System Convergence Tolerance = 1.0e7
Nonlinear System Max Iterations = 1
Nonlinear System Newton After Iterations = 3
Nonlinear System Newton After Tolerance = 1.0e3
Nonlinear System Relaxation Factor = 1
Linear System Solver = Iterative
Linear System Iterative Method = BiCGStab
Linear System Max Iterations = 500
Linear System Convergence Tolerance = 1.0e10
BiCGstabl polynomial degree = 2
Linear System Preconditioning = ILU3
Linear System ILUT Tolerance = 1.0e3
Linear System Abort Not Converged = True
Linear System Residual Output = 10
Linear System Precondition Recompute = 1
End
Equation 1
Name = "Equation 1"
Calculate Stresses = True
Active Solvers(1) = 1
End
Material 1
Name = "Steel (carbon  generic)"
Heat Conductivity = 44.8
Density = 7850.0
Poisson ratio = 0.285
Electric Conductivity = 1.449e6
Electric Conductivity = 1.449e6
Heat expansion Coefficient = 13.8e6
Porosity Model = Always saturated
Electric Conductivity = 1.449e6
Electric Conductivity = 1.449e6
Mesh Poisson ratio = 0.285
Poisson ratio = 0.285
Heat Capacity = 1265.0
Youngs modulus = 200.0e9
Sound speed = 5100.0
Youngs modulus = 200.0e9
Youngs modulus = 200.0e9
Poisson ratio = 0.285
Electric Conductivity = 1.449e6
End
Boundary Condition 1
Target Boundaries(2) = 2 1
Name = "fixed"
Displacement 3 = 0
Displacement 2 = 0
Displacement 1 = 0
End
Boundary Condition 2
Target Boundaries(1) = 4
Name = "load"
Target Coordinates (1,3)= 500.0 0.0 50.0
Force 2 =1.0e+07
End
SUMMARY
FINITE ELEMENT MESH
Mesh dimension: 3
Leading element dimension: 3
Nodes: 26843
Volume elements: 127425
Surface elements: 24816
Edge elements: 37224
Point elements: 0
ELEMENT TYPES
504: 127425
303: 24816
202: 37224
BOUNDING BOX
Xcoordinate: [ 0 , 1000 ]
Ycoordinate: [ 1 , 49 ]
Zcoordinate: [ 0 , 100 ]
GENERAL
Equations: 1
Materials: 1
Boundary conditions: 0
Body properties: 1
VOLUME BODIES
Body 1: 127425 volume elements
Undetermined: 0
Total: 1 volume bodies
SURFACE BODIES
Undetermined: 0
Total: 0 surface bodies
EDGE BODIES
Undetermined: 0
Total: 0 edge bodies
SURFACE BOUNDARIES
Boundary 1: 452 surface elements
Boundary 2: 444 surface elements
Boundary 3: 7914 surface elements
Boundary 4: 7876 surface elements
Boundary 5: 4070 surface elements
Boundary 6: 4060 surface elements
Undetermined: 0
Total: 6 surface boundaries
EDGE BOUNDARIES
Undetermined: 0
Total: 0 edge boundaries
I have checked Target Coordinate Command by Physical Calculation.
The Load shows Equally Distributed and not Point load or line load at target Coordinate.
I have check for both linear and non linear, displacement is same.
Kindly check below and correct myself.
Header
CHECK KEYWORDS Warn
Mesh DB "." "."
Include Path ""
Results Directory ""
End
Simulation
Max Output Level = 5
Coordinate System = Cartesian
Coordinate Mapping(3) = 1 2 3
Simulation Type = Steady state
Steady State Max Iterations = 1
Output Intervals = 1
Timestepping Method = BDF
BDF Order = 1
Coordinate Scaling = 0.001 0.001 0.001
Solver Input File = case.sif
Post File = case.vtu
End
Constants
Gravity(4) = 0 1 0 9.82
Stefan Boltzmann = 5.67e08
Permittivity of Vacuum = 8.8542e12
Boltzmann Constant = 1.3807e23
Unit Charge = 1.602e19
End
Body 1
Target Bodies(1) = 1
Name = "Body 1"
Equation = 1
Material = 1
End
Solver 1
Equation = Linear elasticity
Procedure = "StressSolve" "StressSolver"
Variable = dofs 3 Displacement
Exec Solver = Always
Stabilize = True
Bubbles = False
Lumped Mass Matrix = False
Optimize Bandwidth = True
Steady State Convergence Tolerance = 1.0e5
Nonlinear System Convergence Tolerance = 1.0e7
Nonlinear System Max Iterations = 1
Nonlinear System Newton After Iterations = 3
Nonlinear System Newton After Tolerance = 1.0e3
Nonlinear System Relaxation Factor = 1
Linear System Solver = Iterative
Linear System Iterative Method = BiCGStab
Linear System Max Iterations = 500
Linear System Convergence Tolerance = 1.0e10
BiCGstabl polynomial degree = 2
Linear System Preconditioning = ILU3
Linear System ILUT Tolerance = 1.0e3
Linear System Abort Not Converged = True
Linear System Residual Output = 10
Linear System Precondition Recompute = 1
End
Equation 1
Name = "Equation 1"
Calculate Stresses = True
Active Solvers(1) = 1
End
Material 1
Name = "Steel (carbon  generic)"
Heat Conductivity = 44.8
Density = 7850.0
Poisson ratio = 0.285
Electric Conductivity = 1.449e6
Electric Conductivity = 1.449e6
Heat expansion Coefficient = 13.8e6
Porosity Model = Always saturated
Electric Conductivity = 1.449e6
Electric Conductivity = 1.449e6
Mesh Poisson ratio = 0.285
Poisson ratio = 0.285
Heat Capacity = 1265.0
Youngs modulus = 200.0e9
Sound speed = 5100.0
Youngs modulus = 200.0e9
Youngs modulus = 200.0e9
Poisson ratio = 0.285
Electric Conductivity = 1.449e6
End
Boundary Condition 1
Target Boundaries(2) = 2 1
Name = "fixed"
Displacement 3 = 0
Displacement 2 = 0
Displacement 1 = 0
End
Boundary Condition 2
Target Boundaries(1) = 4
Name = "load"
Target Coordinates (1,3)= 500.0 0.0 50.0
Force 2 =1.0e+07
End
SUMMARY
FINITE ELEMENT MESH
Mesh dimension: 3
Leading element dimension: 3
Nodes: 26843
Volume elements: 127425
Surface elements: 24816
Edge elements: 37224
Point elements: 0
ELEMENT TYPES
504: 127425
303: 24816
202: 37224
BOUNDING BOX
Xcoordinate: [ 0 , 1000 ]
Ycoordinate: [ 1 , 49 ]
Zcoordinate: [ 0 , 100 ]
GENERAL
Equations: 1
Materials: 1
Boundary conditions: 0
Body properties: 1
VOLUME BODIES
Body 1: 127425 volume elements
Undetermined: 0
Total: 1 volume bodies
SURFACE BODIES
Undetermined: 0
Total: 0 surface bodies
EDGE BODIES
Undetermined: 0
Total: 0 edge bodies
SURFACE BOUNDARIES
Boundary 1: 452 surface elements
Boundary 2: 444 surface elements
Boundary 3: 7914 surface elements
Boundary 4: 7876 surface elements
Boundary 5: 4070 surface elements
Boundary 6: 4060 surface elements
Undetermined: 0
Total: 6 surface boundaries
EDGE BOUNDARIES
Undetermined: 0
Total: 0 edge boundaries
 Attachments

 pview.png (30.36 KiB) Viewed 66 times
Re: Elmer Install on Windows 10 not working
Try with
Boundary Condition 2
Name = "load"
Target Coordinates(1,3) = 500.0 0.0 50.0
Displacement 2 Load = 1.0e+07
End
 Mika
Boundary Condition 2
Name = "load"
Target Coordinates(1,3) = 500.0 0.0 50.0
Displacement 2 Load = 1.0e+07
End
 Mika

 Posts: 27
 Joined: 24 Jul 2019, 08:14
 Antispam: Yes
Re: Elmer Install on Windows 10 not working
Boundary Condition 1
Target Boundaries(1) = 4
Name = "load"
Force 2 = "load"
Target Coordinates (1,3)= 500.0 0.0 50.0
load = 1.0e+07
Real MATC "(Force 2, Target Coordinates (1,3))"
End
Boundary Condition 2
Target Boundaries(2) = 2 1
Name = "fixed"
Displacement 3 = 0
Displacement 2 = 0
Displacement 1 = 0
End
refer attachment for paraview output
Target Boundaries(1) = 4
Name = "load"
Force 2 = "load"
Target Coordinates (1,3)= 500.0 0.0 50.0
load = 1.0e+07
Real MATC "(Force 2, Target Coordinates (1,3))"
End
Boundary Condition 2
Target Boundaries(2) = 2 1
Name = "fixed"
Displacement 3 = 0
Displacement 2 = 0
Displacement 1 = 0
End
refer attachment for paraview output
 Attachments

 shot.png (9.28 KiB) Viewed 37 times

 Posts: 27
 Joined: 24 Jul 2019, 08:14
 Antispam: Yes
Re: Elmer Install on Windows 10 not working
ELMER Team Must make this Problem Simple.
Load at Exact Point in terms of Coordinates (x,y,z) Must be Able to Define by define by Mouse... Arrow Mark.
Load at Exact Point in terms of Coordinates (x,y,z) Must be Able to Define by define by Mouse... Arrow Mark.

 Posts: 27
 Joined: 24 Jul 2019, 08:14
 Antispam: Yes
Re: Elmer Install on Windows 10 not working
Boundary Condition 1
Target Boundaries(1) = 4
Name = "load"
Force 2 = "load"
Target Coordinates (1,3)= 500.0 0.0 50.0
load = 1.0e+07
Real MATC "(load, Target Coordinates (1,3))"
End
Boundary Condition 2
Target Boundaries(2) = 2 1
Name = "fixed"
Displacement 3 = 0
Displacement 2 = 0
Displacement 1 = 0
End
refer paraview output same as above...MATC command not defining coordinates at exact distance,,,but defines predefine deformation on x and z axis..by 500mm and 50mm..
Target Boundaries(1) = 4
Name = "load"
Force 2 = "load"
Target Coordinates (1,3)= 500.0 0.0 50.0
load = 1.0e+07
Real MATC "(load, Target Coordinates (1,3))"
End
Boundary Condition 2
Target Boundaries(2) = 2 1
Name = "fixed"
Displacement 3 = 0
Displacement 2 = 0
Displacement 1 = 0
End
refer paraview output same as above...MATC command not defining coordinates at exact distance,,,but defines predefine deformation on x and z axis..by 500mm and 50mm..
 Attachments

 shot1.png (13.1 KiB) Viewed 37 times