Elmer Discussion Forum

Hi Rodrigo
Yes, my test case was a 2D simulation. I didn't try it for 3D simulations myself but I think it will also work for 3D problems. The extension from 2D to 3D must be straightforward.
Regards, Hamed

Hi Paolo Welcome to Elmer. I guess the problem is related to one of the input data of type "Real" that has not been entered appropriately. Try replacing for example "Force 2 = - 5000" with "Force 2 = - 5000.0" and "Displacement 3 = 0" with "Displacement 3...

Hi Ali
This problem is most likely due to sensitivity to the ratio of the vertical length of the ElmerPost window (Elmer Post Graphics window) to its horizontal size. So just simply re-size the window by mouse and and press loop button each time til it gets ok.
Regards, Hamed

Dear Elmer group
I'm still waiting for the modification to be added to the windows-binary. Do I have to wait too long for an update from SVN-4440?
Regards, Hamed

Hi Rodrigo Yes, you have to add it to your sif file. Below I add two of my old sif files that will give you further help. You can follow either of them but the 1st one is more accurate. Take a special look at "boundary condition 3" where I wanted to calculate forces in both sif files. Rega...

Hi Rodrigo Take a look at the following post, it will help much. http://www.elmerfem.org/forum/viewtopic.php?f=7&t=32&p=98&hilit=drag#p98 Besides: Solver 2 Exec Solver = After All Equation = Fluidic Force Procedure ="FluidicForce" "ForceCompute" Calculate Viscous Forc...

Hi Peter
Thanks for your kind comment. I tried it but the problem is that only boundary surfaces are displaced in 3D by color mesh as if the body is hollow so that it is not possible to e.g. view the velocity contour inside the 3D channel. Do you have any solution for this problem?
Regards, Hamed

Dear Elmer group
Is it possible to have a cut-view of the 3D results in post processing facilities of Elmer, for example to see the velocity contour inside a 3D channel?
Regards, Hamed

Dear Legris
In 3D problems the sequence of coordinates is x,y,z but in axi-symmetric problems it is r,teta,z while the variable (displacement) change along the teta direction is zero. So I think you should set displacement 2=0.0 which is equivalent to displacement teta=0.0.
Regards, Hamed

Dear Peter
I attached my testcase including SIF, Elmerstartinfo and mesh files to this post. Can you have a look at it please? Did you check VMS for 3D problems in Elmer?
Regards, Hamed