Elmer Discussion Forum

Unfortunately the historical choice of some keywords may cause confusion. The keyword "External Pressure" basically defines the surface traction (surface force) s applied to the fluid by the environment in terms of unit normal vector n to the boundary as s(n) = p_ext n. If we neglect visco...

There was another bug in the computation of magnetic field strength. This has now been fixed in the devel branch.

Thanks for reporting,
Mika

Hi, I found a bug in the reluctivity evaluation when the constant "Permeability of Vacuum" was given by the user in the constants section. This has now been fixed in the devel branch. The error wasn't nevertheless just a multiplication by four, so I'm not sure whether this explains your ob...

Hi,

I believe these issues have now been fixed in the devel branch of the code repository.

Thanks for reporting,
Mika

Unfortunately I observed that the postprocessing solver (MagnetoDynamicsCalcFields) has neglected the magnetization vector when the magnetization vector has been given in a material section or only elemental approximations have been calculated. This has now been corrected in the devel branch of the ...

Does the Helmholtz Solver support p-elements? Yes What would be the best way to figure out if a solver supports p-elements? Is trial error a viable way (i.e. will solvers not supporting p-elements produce an error in the logs if the keyword is set?) Unfortunately it is not usually clearly indicated...

raback wrote: ↑22 Nov 2020, 14:55 . Also EMWaveSolver exists for transient problems. These both work for 3D only.

EMWaveSolver works in both 2D and 3D cases (in the case of 2D simulation the command "Use Piola Transform = True" must however be given in the sif file).

Hi, To have an example I updated the test case https://github.com/ElmerCSC/elmerfem/tree/devel/fem/tests/mgdyn_bh so that the coenergy is evaluated. This produces to standard output the lines SaveScalars: Showing computed results: SaveScalars: 1: res: eddy current power 0.000000000000E+000 SaveScala...

Hi,

I made a small change to the Calcfields postprocessor (available in the devel branch of the code repository). Now, if you give "Separate Magnetic Energy = True" for this solver, then the solver should also output the magnetic coenergy.

Best regards,
Mika

Hi, Is the electrical conductivity specified to be zero in the inductor (the source part of the model)? I believe the model should be set up such that in the inductor the magnetic induction B satisfies curl(nu*B) = J, with J being the given source, and thus the electrical conductivity should be zero...